AP Physics 1 · Unit 2: Force & Translational Dynamics
2.7 Circular Motion
Centripetal Acceleration
An object moving in a circle at constant speed still accelerates because its velocity direction constantly changes. This acceleration, called centripetal acceleration, always points toward the center of the circle. Its magnitude is a_c = v²/r, where v is speed and r is the radius. No acceleration means no net force, so circular motion always requires a net inward force.
Net Force Causes the Turn
There's no separate 'centripetal force' — it's just the net force directed toward the center, supplied by real forces like tension, gravity, friction, or normal force. Using Newton's second law: F_net = ma_c = mv²/r. To solve circular motion problems, identify all real forces, sum their components toward the center, and set that sum equal to mv²/r.
Common Scenarios
In a vertical circle (like a roller coaster loop), the net inward force changes composition depending on position: at the top, gravity and normal force both point toward the center; at the bottom, normal force must overcome gravity. For a car on a flat curve, friction provides the centripetal force; on a banked curve, the normal force also contributes toward the center.
Key terms
- Centripetal acceleration formula
- a_c = v²/r, directed toward the center of the circular path.
- Is there a special 'centripetal force'?
- No — centripetal force is just the net force (from real forces like tension, gravity, friction, normal) pointing toward the center.
- Newton's second law for circular motion
- F_net = ma_c = mv²/r, where F_net is the sum of all real forces directed toward the center.
- Top of a vertical loop
- Both gravity and normal force point toward the center (downward), combining to supply centripetal force.
- Flat curve driving
- Friction between tires and road provides the centripetal force needed to keep the car turning.
Try an AP-style question
A car moves at 10 m/s around a curve of radius 5 m. What is its centripetal acceleration?
- 20 m/s²
- 50 m/s²
- 2 m/s²
- 0.5 m/s²
Show the answer
A. v²/r.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 2.7 free in APrep