AP Physics 1 · Unit 2: Force & Translational Dynamics
2.6 Applications of Newton's Second Law
Setting up the problem
Applying Newton's Second Law starts with a free-body diagram identifying all forces on an object. Choose axes (often along/perpendicular to motion or an incline), sum forces in each direction, and set them equal to ma. For systems with multiple objects, apply ΣF = ma to each object separately, using Newton's Third Law pairs and shared acceleration/tension as links.
Inclines and friction
On an inclined plane, decompose gravity into components: mg sinθ (parallel to surface) and mg cosθ (perpendicular). Normal force balances the perpendicular component, and friction (f = μN) opposes relative motion or impending motion along the surface. Static friction adjusts up to μₛN to prevent sliding; kinetic friction is μₖN once sliding occurs.
Connected objects & pulleys
For objects connected by strings over pulleys (like Atwood machines), assume massless, inextensible strings and frictionless, massless pulleys unless stated otherwise. Tension is the same throughout a single string, and both masses share the same magnitude of acceleration. Write ΣF = ma for each mass, then solve the system simultaneously.
Key terms
- Free-body diagram
- A diagram showing all forces acting on a single object, used to apply Newton's Second Law.
- Incline force components
- Gravity splits into mg sinθ (parallel to surface, causes sliding) and mg cosθ (perpendicular, balanced by normal force).
- Kinetic vs. static friction
- Static friction (up to μₛN) prevents motion from starting; kinetic friction (μₖN) acts once objects are sliding, typically μₖ < μₛ.
- Atwood machine
- Two masses connected by a string over a pulley; shared tension and acceleration magnitude let you solve ΣF = ma for each mass simultaneously.
- Apparent weight in accelerating elevator
- N = m(g ± a); normal force increases when accelerating upward and decreases when accelerating downward.
Try an AP-style question
A block slides down a frictionless 30° incline. What is its acceleration? (g ≈ 10 m/s²)
- 5 m/s²
- 0 m/s²
- 8.7 m/s²
- 10 m/s²
Show the answer
A. g sin 30°.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 2.6 free in APrep