AP Calculus AB · Unit 1: Limits & Continuity
1.8 The Squeeze Theorem
The idea
The Squeeze Theorem (Sandwich Theorem): if g(x) ≤ f(x) ≤ h(x) near c, and lim g = lim h = L, then f is trapped and lim f = L too.
Classic uses
It proves limits that resist algebra, like lim(x→0) sin(x)/x = 1 and lim(x→0) x²·sin(1/x) = 0 (since −x² ≤ x²sin(1/x) ≤ x², and both bounds → 0).
Key terms
- Squeeze Theorem
- If g ≤ f ≤ h near c and lim g = lim h = L, then lim f = L.
- Also called
- The Sandwich Theorem.
- Key condition
- The two bounding functions must have the same limit at c.
- sin(x)/x
- lim(x→0) sin(x)/x = 1.
- x²·sin(1/x)
- lim(x→0) x²·sin(1/x) = 0 by squeezing between ±x².
Try an AP-style question
If 1 − x² ≤ f(x) ≤ 1 + x² for all x near 0, what is lim(x→0) f(x)?
- 0
- Cannot be determined
- 1
- 2
Show the answer
C. Both bounds approach 1 as x → 0, so f is squeezed to 1.
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