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AP Calculus AB · Unit 1: Limits & Continuity

1.8 The Squeeze Theorem

The idea

The Squeeze Theorem (Sandwich Theorem): if g(x) ≤ f(x) ≤ h(x) near c, and lim g = lim h = L, then f is trapped and lim f = L too.

Classic uses

It proves limits that resist algebra, like lim(x→0) sin(x)/x = 1 and lim(x→0) x²·sin(1/x) = 0 (since −x² ≤ x²sin(1/x) ≤ x², and both bounds → 0).

Key terms

Squeeze Theorem
If g ≤ f ≤ h near c and lim g = lim h = L, then lim f = L.
Also called
The Sandwich Theorem.
Key condition
The two bounding functions must have the same limit at c.
sin(x)/x
lim(x→0) sin(x)/x = 1.
x²·sin(1/x)
lim(x→0) x²·sin(1/x) = 0 by squeezing between ±x².

Try an AP-style question

If 1 − x² ≤ f(x) ≤ 1 + x² for all x near 0, what is lim(x→0) f(x)?

  1. 0
  2. Cannot be determined
  3. 1
  4. 2
Show the answer

C. Both bounds approach 1 as x → 0, so f is squeezed to 1.

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