AP Physics C: Mechanics · Unit 4: Linear Momentum
4.2 Change in Momentum and Impulse
Impulse-Momentum Theorem
Impulse (J) equals the change in momentum: J = Δp = m·Δv. Impulse is also defined as the integral of force over time: J = ∫F dt. Since force and momentum are vectors, impulse is a vector too, pointing in the same direction as the net force applied over that time interval.
Force–Time Graphs
When force varies with time, impulse equals the area under the F-t curve. For constant force, J = F·Δt. This lets you calculate impulse from graphs without knowing the exact force function, using geometry (rectangles, triangles) or calculus (integration) depending on the shape of the curve.
Real-World Applications
Increasing the time of collision (Δt) while keeping impulse constant reduces the average force experienced — this is why airbags, padding, and bending your knees when landing reduce injury. Since J = FΔt is fixed by the momentum change, a longer Δt means a smaller average F.
Key terms
- Impulse (J)
- The change in momentum of an object; J = Δp = ∫F dt, a vector quantity.
- Impulse-Momentum Theorem
- States that the net impulse on an object equals its change in momentum: J = Δp = mΔv.
- Impulse from constant force
- J = F·Δt when force is constant over the time interval.
- Impulse on F-t graph
- Equal to the area under the force vs. time curve.
- Why extending collision time helps
- Since impulse is fixed by Δp, increasing Δt decreases the average force (F = J/Δt), reducing injury or damage.
Try an AP-style question
F(t) = 10t N acts from t = 0 to t = 2 s. What impulse does it deliver?
- 10 N·s
- 20 N·s
- 40 N·s
- 5 N·s
Show the answer
B. ∫₀² 10t dt.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 4.2 free in APrep