AP Physics C: E&M · Unit 6: Electromagnetic Induction
6.3 RL Circuits
Inductors resist current change
An inductor develops an EMF opposing changes in current: EMF = -L(dI/dt), where L is inductance in henries. In an RL circuit with a resistor and inductor, this self-induced EMF delays how fast current can build up or decay, unlike resistors alone which respond instantly.
Charging an RL circuit
When a battery is connected, Kirchhoff's voltage law gives ε = IR + L(dI/dt). Solving this differential equation yields I(t) = (ε/R)(1 - e^(-t/τ)), where the time constant τ = L/R. Current rises exponentially toward its max value ε/R, starting at zero because the inductor initially opposes any current change.
Decaying current
If the battery is removed and the circuit is shorted, current decays as I(t) = I₀e^(-t/τ), with τ = L/R again. The inductor's stored energy (U = ½LI²) drives current through the resistor until it dissipates. Larger L slows the decay/growth; larger R speeds it up.
Key terms
- Inductor EMF formula
- EMF = -L(dI/dt); opposes changes in current, with L the inductance (henries).
- RL time constant
- τ = L/R; time for current to reach ~63% of its final value (charging) or decay to ~37% (discharging).
- Charging current in RL circuit
- I(t) = (ε/R)(1 - e^(-t/τ)); starts at 0, approaches ε/R as t → ∞.
- Decaying current in RL circuit
- I(t) = I₀e^(-t/τ); current decreases exponentially as stored magnetic energy dissipates through R.
- Energy stored in an inductor
- U = ½LI²; represents energy stored in the inductor's magnetic field.
Try an AP-style question
What is the time constant of an RL circuit with L = 2 H and R = 4 Ω?
- 0.5 s
- 2 s
- 0.125 s
- 8 s
Show the answer
A. τ = L/R.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 6.3 free in APrep