AP Physics C: E&M · Unit 4: Electric Circuits
4.4 Capacitors in Circuits
Capacitors resist sudden voltage change
A capacitor stores charge, and its voltage cannot change instantaneously. Just after switching, an uncharged capacitor acts like a wire (0V), and a fully charged capacitor acts like an open circuit (no current flows through it). Between these extremes, charge builds up exponentially as current decays.
RC circuit equations
For a charging capacitor: q(t) = Cε(1 − e^(−t/RC)), and current I(t) = (ε/R)e^(−t/RC). For discharging: q(t) = Q₀e^(−t/RC), I(t) = -(Q₀/RC)e^(−t/RC). The time constant τ = RC sets how fast charge/current change — after one τ, charge is ~63% of max (charging) or ~37% remaining (discharging).
Energy and combinations
Energy stored: U = ½QV = ½CV² = Q²/2C. Capacitors in series share the same charge Q, with 1/C_eq = Σ(1/Cᵢ); in parallel they share the same voltage V, with C_eq = ΣCᵢ. In circuit analysis, apply Kirchhoff's rules combined with these charge/voltage relationships, using derivatives (dq/dt = I) to connect current and charge.
Key terms
- Capacitor at t = 0 (uncharged, switch just closed)
- Acts like a wire — zero voltage drop, allows current to flow freely.
- Capacitor at t → ∞ (fully charged)
- Acts like an open circuit — no current flows, voltage across it equals EMF (in simple loops).
- Time constant τ
- τ = RC; the time for charge/current to change by a factor of e (~63% charged or ~37% remaining).
- Energy stored in a capacitor
- U = ½QV = ½CV² = Q²/2C
- Series vs. parallel capacitors
- Series: same Q, 1/C_eq = Σ(1/Cᵢ). Parallel: same V, C_eq = ΣCᵢ.
Try an AP-style question
In steady state, how much current flows through a branch containing a capacitor?
- None
- The full circuit current
- It oscillates
- Half the circuit current
Show the answer
A. Fully charged capacitor blocks DC.
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