AP Physics C: E&M · Unit 3: Conductors & Capacitors
3.2 Capacitance
What is capacitance?
Capacitance (C) measures a conductor's ability to store charge per unit potential difference: C = Q/V. It depends only on the geometry of the conductors (size, shape, separation) and the material between them, not on Q or V themselves. Units are farads (F), where 1 F = 1 C/V.
Parallel-plate capacitor
For a parallel-plate capacitor, C = ε₀A/d, where A is plate area and d is separation. Applying Gauss's Law gives the field E = σ/ε₀ between plates, and integrating E over distance gives V = Ed. Combining Q = σA with V = Ed yields the formula, showing C increases with larger area and decreases with larger separation.
Energy stored in a capacitor
Charging a capacitor requires work since charge must be moved against an increasing field. The energy stored is U = ½QV = ½CV² = Q²/2C. This energy is stored in the electric field between the plates, and can be found by integrating the work dW = V dq from 0 to Q.
Key terms
- Capacitance formula
- C = Q/V, where Q is stored charge and V is potential difference; measured in farads (F).
- Parallel-plate capacitance
- C = ε₀A/d, derived from Gauss's Law field E = σ/ε₀ and V = Ed.
- Energy stored in a capacitor
- U = ½QV = ½CV² = Q²/2C, found by integrating dW = V dq from 0 to Q.
- Farad
- The SI unit of capacitance; 1 F = 1 C/V.
- Does capacitance depend on Q or V?
- No — capacitance depends only on the geometry of the conductors and the dielectric medium between them.
Try an AP-style question
A parallel-plate capacitor has plate area 0.01 m² and separation 1 mm. What is C? (ε₀ = 8.85 × 10⁻¹²)
- 8.85 × 10⁻⁹ F
- 8.85 × 10⁻¹² F
- 8.85 × 10⁻¹¹ F
- 8.85 × 10⁻¹⁴ F
Show the answer
C. ε₀A/d.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 3.2 free in APrep