AP Physics C: E&M · Unit 2: Electric Potential
2.6 Electric Field and Potential
Field as the Negative Gradient of Potential
The electric field is the negative spatial derivative of electric potential: E = -dV/dr (or E = -∇V in 3D). This means the field points in the direction of steepest decrease in potential, and its magnitude reflects how fast V changes with position. Regions of closely spaced equipotential surfaces have strong fields; widely spaced ones have weak fields.
Getting Potential from the Field
Conversely, potential difference is found by integrating the field: ΔV = -∫E·dr along a path between two points. This is path-independent since E is a conservative field. For a uniform field, this simplifies to ΔV = -E·d, where d is displacement along the field direction.
Equipotentials and Field Lines
Equipotential surfaces are always perpendicular to electric field lines, since moving along an equipotential does no work (E·dr = 0 means E ⊥ dr). Field lines point from high to low potential. No work is done moving a charge along an equipotential surface.
Key terms
- E = -dV/dr
- Electric field is the negative gradient of potential; field points toward decreasing potential.
- ΔV = -∫E·dr
- Potential difference is the negative line integral of the electric field along any path between two points.
- Equipotential surface
- A surface where potential is constant; always perpendicular to electric field lines.
- Uniform field potential formula
- ΔV = -Ed, where d is displacement along the direction of the field.
- Conservative field property
- Work done by the electric field (and thus ΔV) is path-independent, depending only on start and end points.
Try an AP-style question
V(x) = 3x² (V). What is E_x at x = 2 m?
- 12 V/m
- −6 V/m
- −12 V/m
- 6 V/m
Show the answer
C. E = −dV/dx = −6x.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 2.6 free in APrep