AP Physics C: E&M · Unit 2: Electric Potential
2.3 Electric Potential Due to a System of Charges
Superposition of Potential
Electric potential is a scalar, so the potential from a system of point charges is found by simple algebraic addition: V = kΣ(qᵢ/rᵢ), where rᵢ is the distance from each charge qᵢ to the point of interest. Unlike electric field, there are no components or directions to worry about — just add signed values.
Continuous Charge Distributions
For continuous charge, replace the sum with an integral: V = k∫(dq/r). Break the object into infinitesimal charge elements dq, express dq in terms of a density (λ, σ, or ρ) and a geometric variable, then integrate over the whole distribution. Choosing the right coordinate system simplifies the setup significantly.
Potential vs. Reference Point
Potential is defined relative to a reference, usually V = 0 at infinity. Since V is scalar and path-independent, you can compute total potential at a point without worrying about the path taken — a major simplification compared to computing electric field, which requires vector addition.
Key terms
- Potential due to a system of point charges
- V = kΣ(qᵢ/rᵢ) — scalar sum of each charge's contribution.
- Potential due to continuous charge distribution
- V = k∫(dq/r), integrating infinitesimal charge elements over the distribution.
- Why is potential easier to combine than electric field?
- Potential is a scalar quantity, so contributions add algebraically without needing vector components.
- Reference point for potential
- Usually chosen so that V = 0 at infinity, far from all charges.
- Potential from equal and opposite charges at equal distance
- Net potential is zero, since scalar contributions +kq/r and −kq/r cancel.
Try an AP-style question
Charges +2 nC and −2 nC are 2 m apart. What is the potential at the midpoint?
- −18 V
- 18 V
- 36 V
- 0
Show the answer
D. Equal and opposite contributions.
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