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AP Chemistry · Unit 9: Thermodynamics & Electrochemistry

9.3 Gibbs Free Energy and Thermodynamic Favorability

Gibbs Free Energy Equation

Gibbs free energy (ΔG) determines whether a process is thermodynamically favorable: ΔG = ΔH − TΔS. A process is favorable when ΔG < 0, unfavorable when ΔG > 0, and at equilibrium when ΔG = 0. T must be in Kelvin. ΔG combines the effects of enthalpy (ΔH) and entropy (ΔS) into a single value predicting spontaneity.

How ΔH, ΔS, and T Interact

Four combinations exist: (−ΔH, +ΔS) always favorable; (+ΔH, −ΔS) always unfavorable; (−ΔH, −ΔS) favorable at low T; (+ΔH, +ΔS) favorable at high T. Temperature acts as a weighting factor on the entropy term, so some reactions switch favorability as temperature changes — this defines a crossover temperature where ΔG = 0.

ΔG and Equilibrium/Work

ΔG relates to the equilibrium constant: ΔG° = −RT ln K. A very negative ΔG° means K > 1 (favors products); a very positive ΔG° means K < 1 (favors reactants). ΔG also represents the maximum useful work a system can do; as a reaction proceeds toward equilibrium, |ΔG| decreases until it reaches zero.

Key terms

Gibbs free energy equation
ΔG = ΔH − TΔS (T in Kelvin); predicts thermodynamic favorability.
ΔG < 0
Process is thermodynamically favorable (spontaneous as written).
ΔH < 0, ΔS > 0
Reaction is favorable at all temperatures.
ΔG° and K relationship
ΔG° = −RT ln K; very negative ΔG° means K >> 1 (favors products).
Crossover temperature
The temperature at which ΔG = 0, marking the switch between favorable and unfavorable conditions when ΔH and ΔS have the same sign.

Try an AP-style question

ΔH = −100 kJ and ΔS = −200 J/K at 298 K. What is ΔG?

  1. About −100 kJ
  2. About −160 kJ
  3. About +40 kJ
  4. About −40 kJ
Show the answer

D. −100 − 298(−0.200) = −40.4 kJ.

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