AP Chemistry · Unit 7: Equilibrium
7.9 Introduction to Le Châtelier's Principle
What Le Châtelier's Principle Says
Le Châtelier's Principle states that if a system at equilibrium is disturbed by a stress (change in concentration, pressure/volume, or temperature), the system shifts in the direction that partially counteracts the stress, establishing a new equilibrium. This shift changes the amounts of reactants and products but the equilibrium constant K stays the same unless temperature changes.
Concentration and Volume/Pressure Stresses
Adding a reactant or product shifts equilibrium away from the added species (consuming it); removing one shifts toward replacing it. Decreasing volume (increasing pressure) shifts equilibrium toward the side with fewer moles of gas; increasing volume shifts toward the side with more moles of gas. If moles of gas are equal on both sides, pressure/volume changes have no effect on position.
Temperature Stress and K
Temperature changes are unique: they actually change the value of K. For an exothermic reaction, increasing temperature shifts equilibrium toward reactants (K decreases); for endothermic reactions, increasing temperature shifts toward products (K increases). Adding a catalyst speeds up both forward and reverse rates equally, so it does not shift equilibrium or change K—it just gets the system to equilibrium faster.
Key terms
- Le Châtelier's Principle
- If a system at equilibrium is stressed, it shifts in the direction that partially counteracts the stress to reach a new equilibrium.
- Effect of adding reactant/product
- Shifts equilibrium away from the added species (toward consuming it) to restore equilibrium.
- Effect of decreasing volume (increasing pressure)
- Shifts equilibrium toward the side with fewer moles of gas.
- Effect of temperature change on K
- Unlike other stresses, temperature changes actually alter K: increasing T increases K for endothermic reactions and decreases K for exothermic reactions.
- Effect of a catalyst on equilibrium
- No shift in position, no change in K—just speeds up reaching equilibrium by increasing both forward and reverse rates equally.
Try an AP-style question
For N₂ + 3H₂ ⇌ 2NH₃, what happens when the volume is decreased?
- It doesn't shift, since only volume changed
- K increases, since the gas is compressed
- The equilibrium shifts right, toward fewer gas moles
- It shifts left, toward the side with more gas moles
Show the answer
C. 4 mol gas → 2 mol gas.
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