AP Chemistry · Unit 7: Equilibrium
7.14 Free Energy of Dissolution
Dissolution as an equilibrium process
Dissolution is governed by ΔG = ΔH − TΔS. A solute dissolves spontaneously when ΔG < 0. Breaking solute-solute and solvent-solvent interactions requires energy (raising ΔH), while forming solute-solvent interactions releases energy. Mixing increases entropy (ΔS > 0) almost always, since dissolved particles are more disordered than in a pure solid or liquid.
Entropy usually drives dissolution
Even when dissolution is endothermic (ΔH > 0), it can still be spontaneous if the positive ΔS term is large enough to make TΔS outweigh ΔH, giving a negative ΔG. This is why many ionic salts dissolve in water despite absorbing heat — the increase in disorder favors dissolving.
Temperature and solubility connection
Because ΔG = ΔH − TΔS, temperature changes affect the sign of ΔG. For endothermic dissolution, increasing T makes the −TΔS term more negative, favoring dissolution (solubility increases with temperature). For exothermic dissolution, raising T can make ΔG less negative, sometimes decreasing solubility.
Key terms
- ΔG = ?
- ΔG = ΔH − TΔS, the equation for Gibbs free energy of a process.
- Spontaneous dissolution condition
- Occurs when ΔG < 0 (negative free energy change).
- Why can endothermic dissolution still occur?
- If the increase in entropy (ΔS) is large enough that TΔS > ΔH, ΔG becomes negative and dissolution is spontaneous.
- Effect of dissolution on entropy
- Entropy usually increases (ΔS > 0) because dissolved particles are more disordered/dispersed than in the pure solute or solvent.
- Temperature's effect on endothermic dissolution
- Raising temperature makes −TΔS more negative, favoring dissolution and often increasing solubility.
Try an AP-style question
Dissolving NH₄NO₃ in water is endothermic but happens on its own. What makes it favorable?
- A catalyst in the water
- A large increase in entropy
- A large release of heat
- A decrease in entropy
Show the answer
B. TΔS outweighs ΔH.
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