AP Chemistry · Unit 7: Equilibrium
7.12 Common-Ion Effect
What is the common-ion effect?
The common-ion effect occurs when a solution's equilibrium shifts because an ion already present is added from another source. Adding a common ion shifts the equilibrium away from producing more of that ion, per Le Châtelier's principle. This decreases the solubility of a slightly soluble salt or changes the dissociation of a weak acid/base.
Effect on solubility equilibria
For a salt like AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq), adding NaCl introduces extra Cl⁻, a common ion. The reaction shifts left (Q > Ksp momentarily), precipitating more AgCl and lowering its molar solubility compared to pure water. The Ksp value itself doesn't change—only the equilibrium position and solubility do.
Effect on weak acid/base equilibria
Adding a common ion to a weak acid or base equilibrium suppresses ionization. For HA ⇌ H⁺ + A⁻, adding extra A⁻ (e.g., from a salt like NaA) shifts equilibrium left, decreasing [H⁺] and raising pH compared to the acid alone. This principle underlies buffer solutions, which resist pH change using conjugate acid-base pairs.
Key terms
- Common-ion effect
- A shift in equilibrium caused by adding an ion already present in the solution, per Le Châtelier's principle.
- Effect on solubility
- Adding a common ion decreases the solubility of a slightly soluble salt by shifting equilibrium toward the solid.
- Effect on weak acid ionization
- Adding the conjugate base (common ion) decreases ionization, lowering [H⁺] and raising pH.
- Does Ksp change with common-ion effect?
- No—Ksp stays constant; only the position of equilibrium and solubility change.
- Connection to buffers
- Buffers use the common-ion effect: adding a conjugate ion suppresses shifts in ionization, stabilizing pH.
Try an AP-style question
Why is AgCl less soluble in 0.10 M NaCl than in pure water?
- The added Cl⁻ shifts the dissolution equilibrium left
- NaCl reacts with AgCl to form a new solid
- Na⁺ ions block AgCl from dissolving
- NaCl changes the value of Ksp
Show the answer
A. Common ion.
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