AP Chemistry · Unit 5: Kinetics
5.3 Concentration Changes Over Time
Integrated rate laws
Each rate law has an integrated form that shows concentration vs. time. Zero-order: [A] = -kt + [A]₀ (linear plot of [A] vs. t). First-order: ln[A] = -kt + ln[A]₀ (linear plot of ln[A] vs. t). Second-order: 1/[A] = kt + 1/[A]₀ (linear plot of 1/[A] vs. t). Graphing data in the right form reveals the order as a straight line.
Using graphs to find order
To determine reaction order from data, plot [A], ln[A], and 1/[A] each against time. Whichever plot is linear reveals the true order — its slope equals ±k (rate constant). This graphical method is a key way experimental data connects to rate law identification.
Half-life
Half-life (t½) is the time for concentration to drop to half its value. For first-order reactions, t½ = 0.693/k and is constant, independent of concentration — a hallmark of first-order kinetics. Zero- and second-order half-lives depend on initial concentration, so they change over the course of the reaction.
Key terms
- Zero-order integrated rate law
- [A] = -kt + [A]₀; linear plot of [A] vs. time, slope = -k.
- First-order integrated rate law
- ln[A] = -kt + ln[A]₀; linear plot of ln[A] vs. time, slope = -k.
- Second-order integrated rate law
- 1/[A] = kt + 1/[A]₀; linear plot of 1/[A] vs. time, slope = k.
- First-order half-life
- t½ = 0.693/k; constant, independent of concentration.
- How to determine reaction order graphically
- Plot [A], ln[A], and 1/[A] each vs. time — whichever graph is linear identifies the order (zero, first, or second, respectively).
Try an AP-style question
For a first-order reaction, which plot is linear?
- ln[A] vs. time
- [A]² vs. time
- 1/[A] vs. time
- [A] vs. time
Show the answer
A. Integrated first-order law.
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