AP Calculus BC · Unit 8: Applications of Integration
8.8 Volumes with Cross Sections: Triangles and Semicircles
Setting up the cross section
When a solid has a base region and cross sections perpendicular to an axis, the volume is found by integrating the area of each slice along that axis: V = ∫ A(x) dx. First find the length of the slice using the boundary curves (this length becomes a side, diameter, or leg depending on the shape), then plug it into the correct area formula.
Triangle cross sections
If the slice length s (from the base region) is a side of an equilateral triangle, area = (√3/4)s². If it's the leg of an isosceles right triangle (leg on the base), area = (1/2)s². If s is the hypotenuse of an isosceles right triangle, area = (1/4)s². Always identify which part of the triangle the base region represents before choosing the formula.
Semicircle cross sections
If the slice length s is the diameter of a semicircle, the radius is s/2, so area = (1/2)π(s/2)² = πs²/8. Set up the integral V = ∫ πs²/8 dx (or dy) between the bounds, where s = s(x) is the distance between the top and bottom curves of the base region.
Key terms
- Volume with cross sections formula
- V = ∫ A(x) dx (or dy), where A(x) is the area of the cross section at each x.
- Area of equilateral triangle, side s
- A = (√3/4)s²
- Area of isosceles right triangle, leg s (on base)
- A = (1/2)s²
- Area of isosceles right triangle, hypotenuse s (on base)
- A = (1/4)s²
- Area of semicircle with diameter s
- A = πs²/8 (since radius = s/2, area = (1/2)π(s/2)²)
Try an AP-style question
What is the area of an equilateral triangle with side s?
- (√3/2)s²
- (√3/4)s²
- (1/2)s²
- s²
Show the answer
B. Height (√3/2)s times base s over 2.
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