AP Calculus BC · Unit 8: Applications of Integration
8.13 The Arc Length of a Smooth, Planar Curve and Distance Traveled
Arc length formula
For a smooth curve y = f(x) on [a, b], the arc length is L = ∫ from a to b of √(1 + (dy/dx)²) dx. This comes from summing tiny hypotenuses of right triangles with legs dx and dy, approximating the curve with infinitely many line segments.
Parametric arc length
If a curve is given parametrically by x(t) and y(t), the arc length over [a, b] is L = ∫ from a to b of √((dx/dt)² + (dy/dt)²) dt. This same formula gives distance traveled by a particle whose position is (x(t), y(t)).
Distance vs. displacement
For particle motion, distance traveled uses speed = √((dx/dt)² + (dy/dt)²) integrated over time, always giving a positive total. This differs from displacement, which is just the net change in position (final minus initial), and can be smaller or even zero.
Key terms
- Arc length formula for y = f(x)
- L = ∫ from a to b of √(1 + (f'(x))²) dx
- Arc length formula for parametric curves
- L = ∫ from a to b of √((x'(t))² + (y'(t))²) dt
- Distance traveled by a particle
- Integral of speed √((x'(t))² + (y'(t))²) over the time interval; always nonnegative.
- Displacement vs. distance
- Displacement is net position change (final − initial); distance traveled is the total path length, always ≥ displacement in magnitude.
- Geometric origin of arc length formula
- Approximating the curve with tiny line segments and applying the Pythagorean theorem: ds = √(dx² + dy²).
Try an AP-style question
Which integral gives the arc length of y = f(x) from x = a to x = b?
- ∫ₐᵇ √(1 + f(x)²) dx
- ∫ₐᵇ √(1 + [f'(x)]²) dx
- ∫ₐᵇ √(f'(x)) dx
- ∫ₐᵇ (1 + f'(x)) dx
Show the answer
B. Pythagorean theorem on tiny pieces: √(dx² + dy²).
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