AP Calculus BC · Unit 6: Integration & Accumulation of Change
6.7 The Fundamental Theorem of Calculus and Definite Integrals
Fundamental Theorem of Calculus (Part 2)
The FTC states that if F is an antiderivative of a continuous function f, then ∫ₐᵇ f(x)dx = F(b) − F(a). This lets you evaluate definite integrals exactly using antiderivatives instead of limits of Riemann sums — connecting integration and differentiation as inverse operations.
Using antiderivatives to evaluate integrals
To compute ∫ₐᵇ f(x)dx: find an antiderivative F(x), then plug in the bounds and subtract: F(b) − F(a). The constant of integration cancels out during subtraction, so you can ignore +C when evaluating definite integrals.
Properties of definite integrals
Key properties: ∫ₐᵃ f(x)dx = 0; ∫ₐᵇ f(x)dx = −∫ᵦᵃ f(x)dx; ∫ₐᵇ f + ∫ᵦᶜ f = ∫ₐᶜ f (additivity over intervals); constants factor out. These properties simplify computing accumulated change and let you split or combine integrals over adjacent intervals.
Key terms
- Fundamental Theorem of Calculus (Part 2)
- ∫ₐᵇ f(x)dx = F(b) − F(a), where F is any antiderivative of continuous f.
- Why +C disappears in definite integrals
- The constant cancels when subtracting F(a) from F(b), since both include the same +C.
- ∫ₐᵃ f(x)dx
- Equals 0 — integrating over a zero-width interval gives no accumulated change.
- Reversing bounds property
- ∫ₐᵇ f(x)dx = −∫ᵦᵃ f(x)dx — swapping limits negates the integral's value.
- Additivity of integrals
- ∫ₐᵇ f(x)dx + ∫ᵦᶜ f(x)dx = ∫ₐᶜ f(x)dx — integrals over adjacent intervals combine.
Try an AP-style question
∫₁³ (2x + 1) dx = ?
- 10
- 12
- 8
- 7
Show the answer
A. [x² + x]₁³ = 12 − 2.
Practice 8 AP-style questions with instant explanations, flashcards and spaced review.
Study 6.7 free in APrep