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AP Calculus BC · Unit 6: Integration & Accumulation of Change

6.5 Interpreting the Behavior of Accumulation Functions Involving Area

Accumulation functions from an integral

An accumulation function g(x) = ∫ₐˣ f(t) dt represents the net signed area from a to x. By the Fundamental Theorem of Calculus, g'(x) = f(x). So the behavior of f (its sign, sign changes, and value) directly controls whether g is increasing, decreasing, or has extrema — even though g itself is defined by an integral, not a formula.

Reading graphs of f to analyze g

If f(x) > 0, g is increasing; if f(x) < 0, g is decreasing. When f changes from positive to negative, g has a local max; negative to positive gives a local min. Since g'(x) = f(x), g''(x) = f'(x), so g is concave up where f is increasing and concave down where f is decreasing — inflection points of g occur where f has local extrema.

Evaluating accumulation at specific points

To find g(x) at a particular x-value, compute the signed area between a and x using geometry (triangles, rectangles, semicircles) or given values. Areas above the x-axis count positively; areas below count negatively. Comparing g at different x-values requires adding/subtracting these signed areas carefully, especially across sign changes of f.

Key terms

Accumulation function
g(x) = ∫ₐˣ f(t) dt, representing net signed area from a to x; g'(x) = f(x).
When is g increasing/decreasing?
g increases where f(x) > 0 and decreases where f(x) < 0, since g' = f.
Local extrema of g
g has a local max where f changes + to −, and a local min where f changes − to +.
Concavity of g
g is concave up where f is increasing, concave down where f is decreasing, since g'' = f'.
Signed area and g(x)
g(x) equals the net signed area between f and the x-axis from a to x — areas below the axis subtract from the total.

Try an AP-style question

Graph

f is positive on (0, 3) and negative on (3, 6). Let g(x) = ∫₀ˣ f(t) dt.

Where does g have its relative maximum on (0, 6)?

  1. x = 1.5
  2. x = 0
  3. x = 6
  4. x = 3
Show the answer

D. g' = f changes from + to − at x = 3.

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