AP Calculus BC · Unit 5: Analytical Applications of Differentiation
5.1 Using the Mean Value Theorem
What the Mean Value Theorem Says
If a function f is continuous on [a, b] and differentiable on (a, b), then there exists at least one c in (a, b) such that f'(c) = (f(b) − f(a)) / (b − a). This means the instantaneous rate of change at c equals the average rate of change over the interval.
Checking Hypotheses First
Before applying MVT, always verify continuity on [a, b] and differentiability on (a, b). If either condition fails (e.g., a corner, discontinuity, or vertical tangent), MVT may not guarantee a valid c exists. Piecewise functions and absolute value functions are common places where differentiability fails.
MVT vs. Rolle's Theorem
Rolle's Theorem is a special case of MVT where f(a) = f(b), guaranteeing a point c where f'(c) = 0. MVT generalizes this to any secant line slope. Both theorems only guarantee existence of c — they don't tell you how many such points exist or their exact value without solving.
Key terms
- Mean Value Theorem (statement)
- If f is continuous on [a, b] and differentiable on (a, b), there exists c in (a, b) such that f'(c) = (f(b) − f(a)) / (b − a).
- MVT hypotheses
- f must be continuous on the closed interval [a, b] and differentiable on the open interval (a, b).
- Rolle's Theorem
- A special case of MVT: if f(a) = f(b), there exists c in (a, b) where f'(c) = 0.
- Geometric meaning of MVT
- There is a point c where the tangent line's slope equals the slope of the secant line connecting (a, f(a)) and (b, f(b)).
- When MVT fails
- If f has a discontinuity or a non-differentiable point (like a corner or vertical tangent) on [a, b], MVT cannot guarantee such a c exists.
Try an AP-style question
For f(x) = x² on [1, 3], what value c satisfies the Mean Value Theorem?
- 2
- 4
- 1.5
- √5
Show the answer
A. Average rate = (9 − 1)/2 = 4. f'(c) = 2c = 4 → c = 2.
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