AP Calculus BC · Unit 2: Differentiation: Definition & Rules
2.10 Finding the Derivatives of Tangent, Cotangent, Secant, and/or Cosecant Functions
Derivatives of tan and cot
Using the quotient rule on sin/cos gives clean results: d/dx[tan x] = sec²x and d/dx[cot x] = -csc²x. Notice the pattern — the 'co' function (cotangent) gets a negative sign, just like cosine's derivative is negative sine. Memorize these as building blocks for the chain rule.
Derivatives of sec and csc
The remaining two: d/dx[sec x] = sec x tan x and d/dx[csc x] = -csc x cot x. Again, the 'co' function (cosecant) picks up the negative sign. Each derivative is the original reciprocal function times its matching 'co-tangent' partner.
Combine with chain rule
These six trig derivatives (sin, cos, tan, cot, sec, csc) are frequently paired with the chain rule when the argument is more complex, like tan(3x²). Always differentiate the outer trig function first using these rules, then multiply by the derivative of the inner function.
Key terms
- d/dx[tan x]
- sec²x
- d/dx[cot x]
- -csc²x
- d/dx[sec x]
- sec x tan x
- d/dx[csc x]
- -csc x cot x
- Pattern for 'co' trig derivatives
- Cotangent and cosecant (the 'co' functions) always have negative derivatives, mirroring cosine's negative derivative.
Try an AP-style question
d/dx (tan x) = ?
- cot x
- sec² x
- −csc² x
- sec x tan x
Show the answer
B. From sin x / cos x with the quotient rule: 1/cos² x.
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