AP Calculus BC · Unit 10: Infinite Sequences & Series
10.3 The nth Term Test for Divergence
The nth Term Test (Divergence Test)
For a series Σaₙ, if lim(n→∞) aₙ ≠ 0 (or the limit doesn't exist), the series must diverge. This is a quick first check before trying other tests. It's based on the idea that if the terms don't shrink to zero, the partial sums can't settle to a finite value.
Only proves divergence — never convergence
If lim aₙ = 0, the test is inconclusive — the series might converge or diverge. The classic example is the harmonic series Σ(1/n): terms go to 0, but the series still diverges. You must use another test (integral, comparison, ratio, etc.) to decide.
Why it works
For a series to converge, the sequence of partial sums must approach a finite limit. This forces consecutive partial sums to get arbitrarily close together, meaning aₙ = Sₙ − Sₙ₋₁ → 0. So a nonzero limit for aₙ directly contradicts convergence, guaranteeing divergence.
Key terms
- nth Term Test for Divergence
- If lim(n→∞) aₙ ≠ 0 (or doesn't exist), then Σaₙ diverges.
- What if lim aₙ = 0?
- The test is inconclusive — the series may converge or diverge; use another test.
- Key limitation of the test
- It can only prove divergence, never prove convergence.
- Harmonic series example
- Σ(1/n): terms → 0, but the series still diverges — shows the test's limit.
- Why the test works
- Convergence requires aₙ = Sₙ − Sₙ₋₁ → 0; if aₙ doesn't → 0, partial sums can't converge.
Try an AP-style question
What does the nth term test say about Σ n/(n + 1)?
- It is inconclusive
- It diverges, because the terms approach 1
- It converges, because the terms are less than 1
- It converges to 1
Show the answer
B. lim aₙ ≠ 0 → divergence.
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