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AP Calculus BC · Unit 10: Infinite Sequences & Series

10.3 The nth Term Test for Divergence

The nth Term Test (Divergence Test)

For a series Σaₙ, if lim(n→∞) aₙ ≠ 0 (or the limit doesn't exist), the series must diverge. This is a quick first check before trying other tests. It's based on the idea that if the terms don't shrink to zero, the partial sums can't settle to a finite value.

Only proves divergence — never convergence

If lim aₙ = 0, the test is inconclusive — the series might converge or diverge. The classic example is the harmonic series Σ(1/n): terms go to 0, but the series still diverges. You must use another test (integral, comparison, ratio, etc.) to decide.

Why it works

For a series to converge, the sequence of partial sums must approach a finite limit. This forces consecutive partial sums to get arbitrarily close together, meaning aₙ = Sₙ − Sₙ₋₁ → 0. So a nonzero limit for aₙ directly contradicts convergence, guaranteeing divergence.

Key terms

nth Term Test for Divergence
If lim(n→∞) aₙ ≠ 0 (or doesn't exist), then Σaₙ diverges.
What if lim aₙ = 0?
The test is inconclusive — the series may converge or diverge; use another test.
Key limitation of the test
It can only prove divergence, never prove convergence.
Harmonic series example
Σ(1/n): terms → 0, but the series still diverges — shows the test's limit.
Why the test works
Convergence requires aₙ = Sₙ − Sₙ₋₁ → 0; if aₙ doesn't → 0, partial sums can't converge.

Try an AP-style question

What does the nth term test say about Σ n/(n + 1)?

  1. It is inconclusive
  2. It diverges, because the terms approach 1
  3. It converges, because the terms are less than 1
  4. It converges to 1
Show the answer

B. lim aₙ ≠ 0 → divergence.

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