AP Calculus BC · Unit 1: Limits & Continuity
1.6 Determining Limits Using Algebraic Manipulation
Why algebraic manipulation?
Direct substitution often gives an indeterminate form like 0/0. When this happens, rewrite the expression using factoring, expanding, rationalizing (multiplying by the conjugate), or combining fractions with a common denominator so the problematic term cancels. After simplifying, substitute again to find the limit.
Factoring technique
For rational functions with 0/0 at x = a, factor numerator and denominator to find common factors, usually (x − a). Canceling removes the discontinuity that caused the indeterminate form, revealing the actual limiting behavior. This works because the limit only cares about values *near* a, not at a.
Rationalizing technique
When a limit involves a square root and gives 0/0, multiply numerator and denominator by the conjugate of the radical expression. This eliminates the root using the difference of squares, often revealing a cancelable factor. Simplify fully before substituting the limiting value.
Key terms
- Indeterminate form
- An expression like 0/0 that doesn't directly reveal the limit's value and requires further manipulation.
- Factoring technique
- Factor numerator/denominator to cancel common factors causing 0/0, then substitute.
- Rationalizing technique
- Multiply by the conjugate to eliminate square roots using difference of squares.
- Common denominator technique
- Combine fractions within an expression into one fraction to simplify before taking the limit.
- Why cancellation works for limits
- Limits depend on function behavior near a point, not at it, so removing a removable discontinuity doesn't change the limit.
Try an AP-style question
lim(x→3) (x² − 9)/(x − 3) = ?
- 6
- 0
- Does not exist
- 3
Show the answer
A. Factor: (x − 3)(x + 3)/(x − 3) = x + 3 → 6.
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