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AP Calculus AB · Unit 8: Applications of Integration

8.8 Volumes: Triangle & Semicircle Cross Sections

Same integral, new area

Still V = ∫ A(x) dx, but A depends on the shape. Equilateral triangle (side s): A = (√3/4)s². Right isosceles triangle (legs s): A = (1/2)s².

Semicircle

Semicircle with diameter s: A = (π/8)s². Plug in the correct area formula, then integrate over [a, b].

Key terms

Same method
V = ∫ A(x) dx with a shape-specific area.
Equilateral triangle
A = (√3/4)s².
Right isosceles triangle
A = (1/2)s² (legs s).
Semicircle
A = (π/8)s² (diameter s).
Key
Use the correct area formula for the shape.

Try an AP-style question

What is the area of an equilateral triangle with side s?

  1. (√3/4)s²
  2. s²
  3. (1/2)s²
  4. (√3/2)s²
Show the answer

A. Height (√3/2)s times base s over 2.

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