AP Calculus AB · Unit 8: Applications of Integration
8.8 Volumes: Triangle & Semicircle Cross Sections
Same integral, new area
Still V = ∫ A(x) dx, but A depends on the shape. Equilateral triangle (side s): A = (√3/4)s². Right isosceles triangle (legs s): A = (1/2)s².
Semicircle
Semicircle with diameter s: A = (π/8)s². Plug in the correct area formula, then integrate over [a, b].
Key terms
- Same method
- V = ∫ A(x) dx with a shape-specific area.
- Equilateral triangle
- A = (√3/4)s².
- Right isosceles triangle
- A = (1/2)s² (legs s).
- Semicircle
- A = (π/8)s² (diameter s).
- Key
- Use the correct area formula for the shape.
Try an AP-style question
What is the area of an equilateral triangle with side s?
- (√3/4)s²
- s²
- (1/2)s²
- (√3/2)s²
Show the answer
A. Height (√3/2)s times base s over 2.
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