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AP Calculus AB · Unit 8: Applications of Integration

8.1 Average Value of a Function

The formula

The average value of f on [a, b] is (1/(b − a))·∫[a to b] f(x) dx — the definite integral divided by the interval length.

Meaning

It's the height of a rectangle over [a, b] with the same area as the region under f. The average value of a constant c is just c.

Key terms

Average value
(1/(b − a))·∫[a to b] f dx.
Divide by
The interval length (b − a).
Meaning
Height of an equal-area rectangle.
Constant f
Its average value is itself.
Uses
A definite integral over the interval width.

Try an AP-style question

What is the average value of f(x) = x² on [0, 3]?

  1. 3
  2. 9/2
  3. 4.5
  4. 9
Show the answer

A. (1/3)∫₀³ x² dx = (1/3)(9) = 3.

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