AP Calculus AB · Unit 5: Analytical Applications of Differentiation
5.5 The Candidates Test
Absolute extrema on [a, b]
To find the absolute (global) max and min on a closed interval: evaluate f at all critical points in (a, b) and at both endpoints a and b.
Compare values
The largest of these f-values is the absolute maximum; the smallest is the absolute minimum. Endpoints must be included because extremes can occur at the ends.
Key terms
- Candidates Test
- Find absolute extrema on a closed interval.
- Candidates
- Critical points and endpoints.
- Absolute max
- The largest candidate f-value.
- Absolute min
- The smallest candidate f-value.
- Endpoints
- Must be included as candidates.
Try an AP-style question
What are the absolute max and min of f(x) = x³ − 3x on [0, 3]?
- Max 2, min −2
- Max 0, min −18
- Max 18, min −2
- Max 18, min 0
Show the answer
C. Candidates: f(0) = 0, f(1) = −2, f(3) = 18.
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