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AP Calculus AB · Unit 5: Analytical Applications of Differentiation

5.5 The Candidates Test

Absolute extrema on [a, b]

To find the absolute (global) max and min on a closed interval: evaluate f at all critical points in (a, b) and at both endpoints a and b.

Compare values

The largest of these f-values is the absolute maximum; the smallest is the absolute minimum. Endpoints must be included because extremes can occur at the ends.

Key terms

Candidates Test
Find absolute extrema on a closed interval.
Candidates
Critical points and endpoints.
Absolute max
The largest candidate f-value.
Absolute min
The smallest candidate f-value.
Endpoints
Must be included as candidates.

Try an AP-style question

What are the absolute max and min of f(x) = x³ − 3x on [0, 3]?

  1. Max 2, min −2
  2. Max 0, min −18
  3. Max 18, min −2
  4. Max 18, min 0
Show the answer

C. Candidates: f(0) = 0, f(1) = −2, f(3) = 18.

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