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AP Calculus AB · Unit 4: Contextual Applications of Differentiation

4.4 Introduction to Related Rates

Linked quantities

Related rates problems involve quantities linked by an equation, all changing with time. Differentiating the relating equation with respect to t (implicit differentiation) produces an equation linking their rates.

First step

The key setup is finding the equation that relates the variables (from geometry or the situation). Example: A = πr² ⇒ dA/dt = 2πr·(dr/dt).

Key terms

Related rates
Quantities linked by an equation, all changing with time.
Differentiate in t
Apply implicit differentiation with respect to time.
First step
Find the equation relating the variables.
Technique
Implicit differentiation.
Example
A = πr² ⇒ dA/dt = 2πr·(dr/dt).

Try an AP-style question

x and y depend on time t, and x² + y² = 25. Differentiating with respect to t gives…

  1. x(dx/dt) + y(dy/dt) = 25
  2. 2x(dx/dt) + 2y = 0
  3. 2x + 2y = 0
  4. 2x(dx/dt) + 2y(dy/dt) = 0
Show the answer

D. Each term needs the chain rule, and the derivative of 25 is 0.

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