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AP Biology · Unit 7: Natural Selection

7.5 Hardy-Weinberg Equilibrium

A 'not evolving' baseline

Hardy-Weinberg equilibrium is a null model: allele frequencies stay constant when a population is not evolving. It holds only if five conditions are met: no mutation, random mating, no gene flow, a very large population, and no natural selection. Deviations from it signal that evolution is happening.

The equations

Using p (dominant allele frequency) and q (recessive): p + q = 1. Genotype frequencies follow p² + 2pq + q² = 1, where p² = homozygous dominant, 2pq = heterozygous, and q² = homozygous recessive. These let you calculate expected frequencies.

Key terms

Hardy-Weinberg equilibrium
A model where allele frequencies stay constant because the population is not evolving.
p + q = 1
The frequencies of the two alleles must add up to 1.
p² + 2pq + q² = 1
Genotype frequencies: p² (hom. dom.) + 2pq (het.) + q² (hom. rec.) = 1.
Five conditions
No mutation, random mating, no gene flow, large population, no selection.
2pq = heterozygotes
The 2pq term gives the frequency of heterozygous individuals.

Try an AP-style question

Data

In a population of 1,000 in Hardy-Weinberg equilibrium, 160 individuals show the recessive phenotype (aa).

What is the frequency of the dominant allele (p)?

  1. 0.84
  2. 0.16
  3. 0.6
  4. 0.4
Show the answer

C. q² = 160/1000 = 0.16, so q = 0.4 and p = 1 − 0.4 = 0.6.

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